American Jenson Brooksby and Australian Alex de Minaur will meet in the final of the ATP 250 tournament in Atlanta, following both qualified on Saturday by beating American Frances Tiafoe and Belarusian Ilya Ivashka respectively.
Brooksby (43rd player in the world), 21, has indeed defeated Tiafoe (N.29), with the score of 6-1, 6-4.
For his part, De Minaur (N.30) won earlier once morest Ivashka (N.53), 28, in three sets 5-7, 6-2, 6-2.
